Problem Statement: -
A heavy door is to be opened or closed by a double-acting cylinder. This door will open or close with two push buttons, one push button is located inside and another push button is located outside. Draw a Ladder Diagram for the Giving Condition.
a) The push button
should only work when the door is either fully open or fully closed.
Number of inputs = 4
PB1: Inside push button
PB2: Outside push button
L1: Limit
switch located at closing position.
L2: Limit
switch located at open position.
Number of outputs = 2
Y1: Left Solenoid of 5/2 control valve
Y2: Right Solenoid of 5/2 control valve
Pneumatic Circuit Diagram:
Possibilities = 24 =16
Description: -
Initially, as
the door is fully closed the L1 limit switch is pressed (L1=1 & L2=0), the
door will only open when any one of the push buttons is pressed (PB1 =1 &
PB2=0 OR PB1=0 & PB2=1)
It is not
possible that both the Limit switches L1 & L2 are pressed at the same
time (L1=1 & L2=1).
Both the
switches are unpressed (L1=0 & L2=0), which means the door is neither fully
opened nor fully closed
As the door is fully closed the L1 limit switch is pressed (L1=0 & L2=1), the door will only open when any one of the push buttons is pressed (PB1 =1 & PB2=0 OR PB1=0 & PB2=1).
Hence, Y1=
(L1) (L2)’ (PB1)’ (PB2) + (L1) (L2)’ (PB1) (PB2)’
= (L1) (L2)’ [(PB1)’ (PB2) + (PB1) (PB2)’]
Y2= (L1)’ (L2)
(PB1)’ (PB2) + (L1)’ (L2) (PB1) (PB2)’
= (L1)’ (L2) [(PB1)’ (PB2) + (PB1) (PB2)’]
Note: - Above
application may be different from actual application. This example is only for
explanation purpose only. We can use this concept in other examples also.
All parameters and graphical representations considered in this example are for
explanation purpose only, parameters or representation may be different in
actual applications. Also, all interlocks are not considered in the application.
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